# Kaya Scodelario

> Kaya Rose Scodelario is an English actress and model. She first came to prominence co-starring on E4's Skins, receiving two Golden Nymph nominations for her portrayal of Effy Stonem. She then took on leading roles in a variety of films, such as Wuthering Heights (2011), the Maze Runner series (2014–2018), Pirates of the Caribbean: Dead Men Tell No Tales (2017), Crawl (2019), and Resident Evil: Welcome to Raccoon City (2021). In 2024, she starred in the action-comedy series The Gentlemen and limited biographical drama series Senna.

*British actress*

**Canonical URL:** https://fame.am/person/kaya-scodelario

## Identity
- **Profile type:** Actor ([Wikidata](https://www.wikidata.org/entity/Q33999))
- **Category:** Actors
- **Country:** United Kingdom
- **Born:** 1992-03-13
- **Status:** living
- **Gender:** female

## Bio

Imported from discovery source: wikidata-dump

## Fame
- **Popularity score:** 70.0 / 100
- **Momentum:** 25.0 / 100  (trend: BREAKOUT)
- **Historical depth:** 37.5 / 100
- **Now attention:** 100.0 / 100
- **Source confidence:** 80.0 / 100
- **Profile completeness:** 90.0 / 100

## Platforms
- **X**: https://x.com/kScodders (@kScodders)
- **INSTAGRAM**: https://www.instagram.com/kayascods/ (@kayascods)
- **FACEBOOK**: https://www.facebook.com/Kaya-Scodelario-115475391875966 (@Kaya-Scodelario-115475391875966)
- **IMDB**: https://www.imdb.com/name/nm2546012/ (@nm2546012)

## Sources
- [Wikiquote](https://ru.wikiquote.org/wiki/%D0%9A%D0%B0%D1%8F_%D0%A1%D0%BA%D0%BE%D0%B4%D0%B5%D0%BB%D0%B0%D1%80%D0%B8%D0%BE)
- [Kaya Scodelario](https://af.wikipedia.org/wiki/Kaya_Scodelario)
- [كايا سكوديلاريو](https://ar.wikipedia.org/wiki/%D9%83%D8%A7%D9%8A%D8%A7_%D8%B3%D9%83%D9%88%D8%AF%D9%8A%D9%84%D8%A7%D8%B1%D9%8A%D9%88)
- [كايا سكوديلاريو](https://arz.wikipedia.org/wiki/%D9%83%D8%A7%D9%8A%D8%A7_%D8%B3%D9%83%D9%88%D8%AF%D9%8A%D9%84%D8%A7%D8%B1%D9%8A%D9%88)
- [کایا اسکودلاریو](https://azb.wikipedia.org/wiki/%DA%A9%D8%A7%DB%8C%D8%A7_%D8%A7%D8%B3%DA%A9%D9%88%D8%AF%D9%84%D8%A7%D8%B1%DB%8C%D9%88)
- [Кая Скадэларыё](https://be_x_old.wikipedia.org/wiki/%D0%9A%D0%B0%D1%8F_%D0%A1%D0%BA%D0%B0%D0%B4%D1%8D%D0%BB%D0%B0%D1%80%D1%8B%D1%91)
- [Кая Скоделарио](https://bg.wikipedia.org/wiki/%D0%9A%D0%B0%D1%8F_%D0%A1%D0%BA%D0%BE%D0%B4%D0%B5%D0%BB%D0%B0%D1%80%D0%B8%D0%BE)
- [কায়া স্কডিলারিয়ো](https://bn.wikipedia.org/wiki/%E0%A6%95%E0%A6%BE%E0%A6%AF%E0%A6%BC%E0%A6%BE_%E0%A6%B8%E0%A7%8D%E0%A6%95%E0%A6%A1%E0%A6%BF%E0%A6%B2%E0%A6%BE%E0%A6%B0%E0%A6%BF%E0%A6%AF%E0%A6%BC%E0%A7%8B)
- [Kaya Scodelario](https://ca.wikipedia.org/wiki/Kaya_Scodelario)
- [Kaya Scodelario](https://cs.wikipedia.org/wiki/Kaya_Scodelario)
- [Kaya Scodelario](https://da.wikipedia.org/wiki/Kaya_Scodelario)
- [Kaya Scodelario](https://de.wikipedia.org/wiki/Kaya_Scodelario)
- [Kaya Scodelario](https://en.wikipedia.org/wiki/Kaya_Scodelario)
- [Kaya Scodelario](https://es.wikipedia.org/wiki/Kaya_Scodelario)
- [Kaya Scodelario](https://et.wikipedia.org/wiki/Kaya_Scodelario)
- [Kaya Scodelario](https://eu.wikipedia.org/wiki/Kaya_Scodelario)
- [کایا اسکودلاریو](https://fa.wikipedia.org/wiki/%DA%A9%D8%A7%DB%8C%D8%A7_%D8%A7%D8%B3%DA%A9%D9%88%D8%AF%D9%84%D8%A7%D8%B1%DB%8C%D9%88)
- [Kaya Scodelario](https://fi.wikipedia.org/wiki/Kaya_Scodelario)
- [Kaya Scodelario](https://fr.wikipedia.org/wiki/Kaya_Scodelario)
- [קאיה סקודלריו](https://he.wikipedia.org/wiki/%D7%A7%D7%90%D7%99%D7%94_%D7%A1%D7%A7%D7%95%D7%93%D7%9C%D7%A8%D7%99%D7%95)
- [Kaya Scodelario](https://hr.wikipedia.org/wiki/Kaya_Scodelario)
- [Kaya Scodelario](https://ht.wikipedia.org/wiki/Kaya_Scodelario)
- [Kaya Scodelario](https://hu.wikipedia.org/wiki/Kaya_Scodelario)
- [Կայա Սկոդելարիո](https://hy.wikipedia.org/wiki/%D4%BF%D5%A1%D5%B5%D5%A1_%D5%8D%D5%AF%D5%B8%D5%A4%D5%A5%D5%AC%D5%A1%D6%80%D5%AB%D5%B8)
- [Kaya Scodelario](https://id.wikipedia.org/wiki/Kaya_Scodelario)
- [Kaya Scodelario](https://it.wikipedia.org/wiki/Kaya_Scodelario)
- [Wikiquote](https://it.wikiquote.org/wiki/Kaya_Scodelario)
- [Wikidata](https://www.wikidata.org/wiki/Q229651)
- [Kaya Scodelario](https://www.themoviedb.org/person/115150)

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