# Holland Taylor

> Holland Taylor is an American actress. She won the 1999 Primetime Emmy Award for Outstanding Supporting Actress in a Drama Series for her role as Judge Roberta Kittleson on ABC's The Practice (1998-2003) and she received four Primetime Emmy Award nominations for her role as Evelyn Harper on Two and a Half Men (2003-15).

*American actress*

**Canonical URL:** https://fame.am/person/holland-taylor

## Identity
- **Profile type:** Actor ([Wikidata](https://www.wikidata.org/entity/Q33999))
- **Category:** Actors
- **Country:** United States
- **Born:** 1943-01-14
- **Status:** living
- **Gender:** female

## Fame
- **Popularity score:** 67.9 / 100
- **Momentum:** 24.8 / 100  (trend: BREAKOUT)
- **Historical depth:** 34.5 / 100
- **Attention shift:** 100.0 / 100
- **Source confidence:** 80.0 / 100
- **Profile completeness:** 90.0 / 100

## Platforms
- **X**: https://x.com/HollandTaylor (@HollandTaylor)
- **INSTAGRAM**: https://www.instagram.com/hollandvtaylor/ (@hollandvtaylor)
- **IMDB**: https://www.imdb.com/name/nm0852466/ (@nm0852466)
- **WEBSITE**: http://www.hollandtaylor.com/

## Sources
- [霍兰·泰勒](https://zh.wikipedia.org/wiki/%E9%9C%8D%E5%85%B0%C2%B7%E6%B3%B0%E5%8B%92)
- [Тейлор, Холланд](https://ru.wikipedia.org/wiki/%D0%A2%D0%B5%D0%B9%D0%BB%D0%BE%D1%80%2C_%D0%A5%D0%BE%D0%BB%D0%BB%D0%B0%D0%BD%D0%B4)
- [Holland Taylor](https://pt.wikipedia.org/wiki/Holland_Taylor)
- [هولند تايلور](https://arz.wikipedia.org/wiki/%D9%87%D9%88%D9%84%D9%86%D8%AF_%D8%AA%D8%A7%D9%8A%D9%84%D9%88%D8%B1)
- [Holland Taylor](https://ast.wikipedia.org/wiki/Holland_Taylor)
- [هالند تیلور](https://azb.wikipedia.org/wiki/%D9%87%D8%A7%D9%84%D9%86%D8%AF_%D8%AA%DB%8C%D9%84%D9%88%D8%B1)
- [Холанд Тейлър](https://bg.wikipedia.org/wiki/%D0%A5%D0%BE%D0%BB%D0%B0%D0%BD%D0%B4_%D0%A2%D0%B5%D0%B9%D0%BB%D1%8A%D1%80)
- [Holland Taylor](https://cs.wikipedia.org/wiki/Holland_Taylor)
- [Holland Taylor](https://cy.wikipedia.org/wiki/Holland_Taylor)
- [Holland Taylor](https://de.wikipedia.org/wiki/Holland_Taylor)
- [Χόλαντ Τέιλορ](https://el.wikipedia.org/wiki/%CE%A7%CF%8C%CE%BB%CE%B1%CE%BD%CF%84_%CE%A4%CE%AD%CE%B9%CE%BB%CE%BF%CF%81)
- [Holland Taylor](https://en.wikipedia.org/wiki/Holland_Taylor)
- [Holland Taylor](https://es.wikipedia.org/wiki/Holland_Taylor)
- [Holland Taylor](https://et.wikipedia.org/wiki/Holland_Taylor)
- [هالند تیلور](https://fa.wikipedia.org/wiki/%D9%87%D8%A7%D9%84%D9%86%D8%AF_%D8%AA%DB%8C%D9%84%D9%88%D8%B1)
- [Holland Taylor](https://fr.wikipedia.org/wiki/Holland_Taylor)
- [הולנד טיילור](https://he.wikipedia.org/wiki/%D7%94%D7%95%D7%9C%D7%A0%D7%93_%D7%98%D7%99%D7%99%D7%9C%D7%95%D7%A8)
- [Holland Taylor](https://hu.wikipedia.org/wiki/Holland_Taylor)
- [Հոլանդ Թեյլոր](https://hy.wikipedia.org/wiki/%D5%80%D5%B8%D5%AC%D5%A1%D5%B6%D5%A4_%D4%B9%D5%A5%D5%B5%D5%AC%D5%B8%D6%80)
- [Holland Taylor](https://id.wikipedia.org/wiki/Holland_Taylor)
- [Holland Taylor](https://it.wikipedia.org/wiki/Holland_Taylor)
- [ホランド・テイラー](https://ja.wikipedia.org/wiki/%E3%83%9B%E3%83%A9%E3%83%B3%E3%83%89%E3%83%BB%E3%83%86%E3%82%A4%E3%83%A9%E3%83%BC)
- [홀랜드 테일러](https://ko.wikipedia.org/wiki/%ED%99%80%EB%9E%9C%EB%93%9C_%ED%85%8C%EC%9D%BC%EB%9F%AC)
- [Holland Taylor](https://nl.wikipedia.org/wiki/Holland_Taylor)
- [Holland Taylor](https://pl.wikipedia.org/wiki/Holland_Taylor)
- [Wikiquote](https://he.wikiquote.org/wiki/%D7%94%D7%95%D7%9C%D7%A0%D7%93_%D7%98%D7%99%D7%99%D7%9C%D7%95%D7%A8)
- [MusicBrainz](https://musicbrainz.org/artist/ee2d9ffd-8310-413d-9f47-da45e0c2aea6)
- [Holland Taylor](https://fi.wikipedia.org/wiki/Holland_Taylor)
- [Holland Taylor](https://af.wikipedia.org/wiki/Holland_Taylor)
- [هولند تايلور](https://ar.wikipedia.org/wiki/%D9%87%D9%88%D9%84%D9%86%D8%AF_%D8%AA%D8%A7%D9%8A%D9%84%D9%88%D8%B1)

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