# Henrietta Swan Leavitt

> Henrietta Swan Leavitt was an American astronomer. Her discovery of how to effectively measure vast astronomical distances led to a shift in the understanding of the scale and nature of the universe.

*American astronomer and human calculator (1868-1921)*

**Canonical URL:** https://fame.am/person/henrietta-swan-leavitt

## Identity
- **Profile type:** Scientist ([Wikidata](https://www.wikidata.org/entity/Q39631))
- **Category:** Scientists
- **Country:** United States
- **Born:** 1868-07-04
- **Died:** 1921-12-12
- **Status:** deceased
- **Gender:** female

## Fame
- **Popularity score:** 56.8 / 100
- **Momentum:** 2.9 / 100  (trend: STABLE)
- **Historical depth:** 24.2 / 100
- **Attention shift:** 11.7 / 100
- **Source confidence:** 60.0 / 100
- **Profile completeness:** 70.0 / 100

## Sources
- [亨丽爱塔·斯万·勒维特](https://zh.wikipedia.org/wiki/%E4%BA%A8%E4%B8%BD%E7%88%B1%E5%A1%94%C2%B7%E6%96%AF%E4%B8%87%C2%B7%E5%8B%92%E7%BB%B4%E7%89%B9)
- [Henrietta Swan Leavitt](https://it.wikipedia.org/wiki/Henrietta_Swan_Leavitt)
- [Henrietta Swan Leavitt](https://pt.wikipedia.org/wiki/Henrietta_Swan_Leavitt)
- [Henrietta Leavitt](https://nl.wikipedia.org/wiki/Henrietta_Leavitt)
- [Henrietta Leavitt](https://pl.wikipedia.org/wiki/Henrietta_Leavitt)
- [Ливитт, Генриетта Суон](https://ru.wikipedia.org/wiki/%D0%9B%D0%B8%D0%B2%D0%B8%D1%82%D1%82%2C_%D0%93%D0%B5%D0%BD%D1%80%D0%B8%D0%B5%D1%82%D1%82%D0%B0_%D0%A1%D1%83%D0%BE%D0%BD)
- [ヘンリエッタ・スワン・リービット](https://ja.wikipedia.org/wiki/%E3%83%98%E3%83%B3%E3%83%AA%E3%82%A8%E3%83%83%E3%82%BF%E3%83%BB%E3%82%B9%E3%83%AF%E3%83%B3%E3%83%BB%E3%83%AA%E3%83%BC%E3%83%93%E3%83%83%E3%83%88)
- [হেনরিয়েটা লেভিট](https://bn.wikipedia.org/wiki/%E0%A6%B9%E0%A7%87%E0%A6%A8%E0%A6%B0%E0%A6%BF%E0%A6%AF%E0%A6%BC%E0%A7%87%E0%A6%9F%E0%A6%BE_%E0%A6%B2%E0%A7%87%E0%A6%AD%E0%A6%BF%E0%A6%9F)
- [Henrietta Swann Leavitt](https://bs.wikipedia.org/wiki/Henrietta_Swann_Leavitt)
- [Henrietta Swan Leavitt](https://ca.wikipedia.org/wiki/Henrietta_Swan_Leavitt)
- [Henrietta Swan Leavittová](https://cs.wikipedia.org/wiki/Henrietta_Swan_Leavittov%C3%A1)
- [Henrietta Swan Leavitt](https://cy.wikipedia.org/wiki/Henrietta_Swan_Leavitt)
- [Henrietta Swan Leavitt](https://da.wikipedia.org/wiki/Henrietta_Swan_Leavitt)
- [Henrietta Swan Leavitt](https://de.wikipedia.org/wiki/Henrietta_Swan_Leavitt)
- [Ενριέττα Σ. Λίβιτ](https://el.wikipedia.org/wiki/%CE%95%CE%BD%CF%81%CE%B9%CE%AD%CF%84%CF%84%CE%B1_%CE%A3._%CE%9B%CE%AF%CE%B2%CE%B9%CF%84)
- [Henrietta Swan Leavitt](https://en.wikipedia.org/wiki/Henrietta_Swan_Leavitt)
- [Henrietta Swan Leavitt](https://eo.wikipedia.org/wiki/Henrietta_Swan_Leavitt)
- [Henrietta Swan Leavitt](https://es.wikipedia.org/wiki/Henrietta_Swan_Leavitt)
- [هنریتا سوان لیویت](https://fa.wikipedia.org/wiki/%D9%87%D9%86%D8%B1%DB%8C%D8%AA%D8%A7_%D8%B3%D9%88%D8%A7%D9%86_%D9%84%DB%8C%D9%88%DB%8C%D8%AA)
- [Henrietta Swan Leavitt](https://fi.wikipedia.org/wiki/Henrietta_Swan_Leavitt)
- [Henrietta Swan Leavitt](https://fr.wikipedia.org/wiki/Henrietta_Swan_Leavitt)
- [Henrietta Swan Leavitt](https://ga.wikipedia.org/wiki/Henrietta_Swan_Leavitt)
- [Henrietta Swan Leavitt](https://gl.wikipedia.org/wiki/Henrietta_Swan_Leavitt)
- [הנרייטה ליוויט](https://he.wikipedia.org/wiki/%D7%94%D7%A0%D7%A8%D7%99%D7%99%D7%98%D7%94_%D7%9C%D7%99%D7%95%D7%95%D7%99%D7%98)
- [Henrietta Leavitt](https://hr.wikipedia.org/wiki/Henrietta_Leavitt)
- [Wikiquote](https://en.wikiquote.org/wiki/Henrietta_Swan_Leavitt)
- [Wikiquote](https://es.wikiquote.org/wiki/Henrietta_Swan_Leavitt)
- [Wikiquote](https://it.wikiquote.org/wiki/Henrietta_Swan_Leavitt)
- [Wikiquote](https://pt.wikiquote.org/wiki/Henrietta_Swan_Leavitt)
- [Henrietta Swan Leavitt](https://eu.wikipedia.org/wiki/Henrietta_Swan_Leavitt)

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